(•) Given the first Newman projection and the direction and degree of rotation, fill in the resulting Newman projection. [One substituent has been labeled for you.] (l)

Hello, everyone. Today, we have the following problem draw the resulting Newman projection based on the initial Newman projection provided and at the indicated direction and degree of rotation. So this newer projection is being rotated 300 degrees counterclockwise. And based on the New Newman projection, our propal group here is remaining the same meaning our front group is not changing. So we will just draw in our hydrogen and our X atom, it looks like we're just rotating about the back carbon. So recall that the angle between, between two bonds originating from different atoms in a newer projection is referred to as the dihedral angle. And so that usually involves two bonds, one involving the front carbon and the back carbon as such. And so that angle is equal to 60 degrees. So if we were to rotate counterclockwise as designated by the arrow counterclockwise, such that the bat carbon moves five times counterclockwise, five times 60 degrees would give us 300 degrees. So that would give us the following new projection. So to simplify the hydrogens, we would simply label hydrogen one and two respectively. And then we would show them the resulting structure as such. And so with that, we have constructed the resulting Newman projection overall, I hope this helped. And until next time.