In this example question, we need to get the product from the following oxidation reaction. So in this question, we have Benzene, and directly connected to it is an OH group. We also have another substituent coming off of Benzene. Here is our benzylic carbon, and on it, our OH group. Here we're doing selective oxidation by using manganese 4 oxide within a dichloromethane solvent.

Remember, this is a very weak oxidation, a selective oxidation that only targets benzylic OH groups. Here is our benzylic carbon with its OH group. So, it's what's going to be oxidized. The other OH group, being directly connected to Benzene, is not benzylic in nature. So it stays as OH.

This alcohol gets oxidized, so we go from an OH group to a carbonyl group. So we're gonna get Cdouble bond O here. So we've gone from a secondary benzylic alcohol into a ketone. This would be our final product. Remember, this type of oxidation is only targeting our benzylic OH group.

The other OH group is unaffected.