the-pb2-ion-can-be-precipitated-using-the-cl-ion-calculate-the-volume-in-ml-of-0

Question

The Pb²⁺ ion can be precipitated using the Cl^– ion. Calculate the volume (in mL) of 0.11 M HCl solution required to react with 40.0 mL of 0.26 M Pb(NO₃)₂. Determine the mass (in grams) of PbCl₂ formed.

Accepted Answer

189 mL HCl
2.89 g PbCl₂

Answer

84.6 mL HCl
1.32 g PbCl₂

Answer

114 mL HCl
1.62 g PbCl₂

Answer

242 mL HCl
3.76 g PbCl₂

The Pb2+ ion can be precipitated using the Cl– ion. Calculate the volume (in mL) of 0.11 M HCl solution required to react with 40.0 mL of 0.26 M Pb(NO3)2. Determine the mass (in grams) of PbCl2 formed.

The Pb²⁺ ion can be precipitated using the Cl^– ion. Calculate the volume (in mL) of 0.11 M HCl solution required to react with 40.0 mL of 0.26 M Pb(NO₃)₂. Determine the mass (in grams) of PbCl₂ formed.