The diploid number of the hypothetical animal Geneticus ...

Question

The diploid number of the hypothetical animal Geneticus introductus is 2n = 36. Each diploid nucleus contains 3 ng of DNA in G₁.

Explain why a somatic cell of Geneticus introductus has the same number of chromosomes and the same amount of DNA at the beginning of mitotic prophase as one of these cells does at the beginning of prophase I of meiosis.

Accepted Answer

Hey, everyone. Let's take a look at this question together. The deployed number of humans is to n equals 46. Which of the following happens to a cell at the end of psychokinesis during biotic cell division. So we know that in biotic cell division, a cell undergoes two rounds of cell division. And at the end of the psychokinesis stage, one cell can produce four hap Lloyd cells which these four hap Lloyd sells means that we have four cells with 23 chromosomes each. So that means that at the end of psychokinesis during biotic cell division, we have four cells with 23 chromosomes each. So that means that answer choice B is the correct answer. Because during biotic cell division, cell undergoes two rounds of cell div and at the end of the site of stage, a single cell can produce four hap Lloyd cells which for hap Lloyd sells means we have four cells with 23 chromosomes each. So answer choice B is the correct answer. I hope you found this video to be helpful. Thank you and goodbye.

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