A female of genotype

a b c
+ + +

produces 100 meiotic tetrads....

Question

A female of genotype a b c + + + produces 100 meiotic tetrads. Of these, 68 show no crossover events. Of the remaining 32, 20 show a crossover between a and b, 10 show a crossover between b and c, and 2 show a double crossover between a and b and between b and c. Of the 400 gametes produced, how many of each of the 8 different genotypes will be produced? Assuming the order a–b–c and the allele arrangement previously shown, what is the map distance between these loci?

Accepted Answer

Hello everyone. Let's look at our next problem. It says the following Diagram shows the genetic map of four linked genes on a chromosome. And we've got jeans, A. B. C. And D. With the distances between many of them marked on our map. What will be the distance between D. And B. What we see here here's our distance that we're looking for between D. And B. But we do have um the distance here between D. And C. Go here and then we have the distance between B. And C. Here. So between those two, the difference is the distance between D. And B. So the distance between D. And C is equal to. And that's this number here, map units. And then the distance between B. And C. Here, that's 12 map units. So between B&C is 12 map units. So therefore the distance between D. And B must be 18 M. U minus 12 M. U. And that's going to equal six. So we go over to the answer choices and choice A. Is indeed six emu. So looking at this diagram, what will be the distance between D. And B. Choice A. Six. M. U. See you in the next video

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