The boss in your laboratory has just heard of a proposal...

Question

The boss in your laboratory has just heard of a proposal by another laboratory that genes for eye color and the length of body bristles may be linked in Drosophila. Your lab has numerous pure-breeding stocks of Drosophila that could be used to verify or refute genetic linkage. In Drosophila, red eyes (c⁺) are dominant to brown eyes (c) and long bristles (d⁺) are dominant to short bristles (d). Your lab boss asks you to design an experiment to test the genetic linkage of eye color and bristle-length genes, and to begin by crossing a pure-breeding line homozygous for red eyes and short bristles to a pure-breeding line that has brown eyes and long bristles.

How would the results of the cross differ if the genes are not linked?

Accepted Answer

Welcome back. Let's look at our next question. It says, suppose we study the genetic linkage of two genes and peas to determine the genetic linkage, we cross a wild type P with a mutant P and obtain offspring with parental configurations and recombinant. We then conducted a test cross in the F one progeny and obtained another set of offspring F two. Using the chi square test, we determine that the genes are not linked. Suppose we used link genes. What can we expect in the computed P value after conducting the chi square test? And our answer choices are a 0.5 b 0. C 0.75 or D 0. or below. Well, let's recall that the P value has that letter P because it gives us the probability that the results are due to random chat. And you get the P value by looking at a chi square table, you calculate your chi squared value and looking at your chi squared value and your degrees of freedom, you can find the P value A P value of 0.05 or below means that there is 5% or less chance that your results are due just two random chants. And as a result, when the P value is less than 0.05, you can reject the null hypothesis. In this case, the, the hypothesis would say that the genes are not linked. So in this case where we've used definitely linked genes, you would expect the P value to be 0.5 or below since the genes are not linked. So our answer choice is choice D 0.05 or below you in the next video.

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