Human albinism is a simple recessive trait. Determine the genotypes of the parents for each offspring combination i. A wild-type male and albino female have 6 wild-type children

Okay. So this question is saying that human albinism is a sing a simple recessive trait. So if you have your homozygous recessive for this trait, then you'll be you'll have albinism. So it says determine the genotypes of the parents for each offspring combination. So the first offspring combination we're looking at is that there is a wild type male and an albino female have 6 wild type children. So the first thing we know is that there's an albino mother, so she automatically has this, this homozygous recessive phenotype. But what we don't know is we don't know if the male is homozygous dominant or if he's heterozygous. So, the first thing we need to do is we just need to mark out some of these answers to make it more do able. So any of these answers, so these are supposed to be the parental genotypes. Right? And we know that one of the parents has to be homozygous recessive. So any of these answers without a homozygous recessive in there is not going to be the answer. So automatically we marked out 3 answers and now it's just a 5050, a or c. So we can just do a Punnett Square and see what type of children we get. So the first Punnett square is going to be this one, and that's going to be a. Right? The second Punnett square we are going to do is homozygous recessive. Right? So if we do this one here, let me disappear, we're going to get all albino children. That's obviously not it. C cannot be the answer. Whereas, if we do this Punnett square, we get all wild type children. The answer here is a. So with that, let's move on.

Human albinism is a simple recessive trait. Determine the genotyp...

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Human albinism is a simple recessive trait. Determine the genotypes of the parents for each offspring combination
i. A wild-type male and albino female have 6 wild-type children