In a cross in Drosophila involving the X-linked recessive eye mut...

Question

In a cross in Drosophila involving the X-linked recessive eye mutation white and the autosomally linked recessive eye mutation sepia (resulting in a dark eye), predict the F₁ and F₂ results of crossing true-breeding parents of the following phenotypes:

Note that white is epistatic to the expression of sepia.

white females x sepia males

Accepted Answer

Hey everyone let's take a look at this question together. Which of the following will have the same expression when A. Is the episodic locus in dominant episode Asus. So let's recall what we've learned about the episodic locus in dominant deepest Asus to try to figure out which of the following will have the same expression. So since A. Is at the episodic locus we only need one set of dominant genes at the A locus. Because dominant epistolary sis occurs when one jeans dominant olio conceals oh other jeans. And so looking at our answer choices, we can see that answer choice B. As both that dominant allele for A. In both options, which means that it is the correct answer because an answer choice is A. We see we only have it once, answer choice C. We don't have that dominant allele in both and then answer choice D. We also only have it once. So they they are all incorrect because in order for us to have the same expression in both, we need to have at least one dominant allele which is that capital A. That we see in both an answer choice B. So answer choice B. Is the only one here that is the correct answer. I hope you found this video to be helpful. Thank you and goodbye

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