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Ch.10 - Chemical Bonding I: The Lewis Model
Chapter 10, Problem 40a,d

Write the Lewis symbols for the ions in each ionic compound. a. SrO d. RbF

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Identify the elements involved in the compound RbF: Rubidium (Rb) and Fluorine (F).
Determine the electron configuration of each element: Rb is in Group 1 with one valence electron, and F is in Group 17 with seven valence electrons.
Understand that Rb will lose one electron to achieve a stable electron configuration, forming Rb⁺, and F will gain one electron to achieve a stable electron configuration, forming F⁻.
Draw the Lewis symbol for Rb⁺: Since Rb loses its one valence electron, its Lewis symbol is Rb with a positive charge, Rb⁺.
Draw the Lewis symbol for F⁻: Since F gains one electron, its Lewis symbol is F with eight dots around it and a negative charge, F⁻.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Lewis Symbols

Lewis symbols, or Lewis dot structures, represent the valence electrons of an atom as dots around the element's symbol. This notation helps visualize how atoms bond and interact in chemical compounds. For ions, the Lewis symbol indicates the loss or gain of electrons, reflecting their charged state.
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Ionic Compounds

Ionic compounds are formed through the electrostatic attraction between positively charged ions (cations) and negatively charged ions (anions). In the case of RbF, rubidium (Rb) donates an electron to fluorine (F), resulting in Rb+ and F- ions. Understanding the formation of these ions is crucial for writing their Lewis symbols.
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Charge of Ions

The charge of an ion is determined by the number of electrons lost or gained compared to the neutral atom. Cations, like Rb+, have a positive charge due to the loss of one electron, while anions, like F-, have a negative charge from gaining an electron. This charge is essential for accurately representing the ions in Lewis symbols.
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