Skip to main content
Ch.5 - Introduction to Solutions and Aqueous Solutions

Chapter 5, Problem 48

Classify each compound as a strong electrolyte or nonelectrolyte. a. K2SO4 b. C6H12O6 c. K2CO3 d. CH3OH

Verified Solution
Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Video transcript

Hi everyone. So as classify each as either a non electrolyte. For a strong electrolyte we call that strong electrolytes. Break up into ions completely. And non electrolytes do not break up into ions at all. Server Casio nitrate is going to associate And it's gonna be CA two plus Plus, you know 3 -. Since we have two nitrate over here we need to put it to in front of you know three. calcium nitrate is a nitrate salt. So that's going to dissociate completely and it's going to be a strong electrolyte first. sodium hydroxide. It's going to break up into an A. Plus and O. H. Minus. And there's a group one hydroxide that's going to completely disassociate. And it's gonna be a strong electrolyte And for c. six H. 1206. It's also known as sugar and this cannot associate at all. So this is gonna be a non electrolyte. Infra sodium bromine is going to associate into N. A. Class. Let's be R minus. And there's a group one salt that's going to completely disassociate and it's gonna be a strong electrolyte. Thanks for watching my video and I hope it was helpful