Balance each chemical equation. b. Co(NO3)3(aq) + (NH4)2S(aq)¡Co2S3(s) + NH4NO3(aq)

Video transcript

Hi everyone here, we have a question asking us to balance a fallen chemical equation cobalt nitrate plus ammonium carbonate forms, cobalt carbonate plus ammonium nitrate. So let's rewrite this. Now let's count what we have on both sides. So on our reactant side we have one cobalt we have three plus two nitrogen, so five We have three times three, so nine oxygen plus three more, so 12 oxygen. And we have four times two hydrogen, so eight hydrogen. And lastly we have one carbon. And on our product side we have to cobalt We have two nitrogen. We have three times three oxygen, so nine oxygen plus three more. So 12 oxygen. We have four hydrogen And we have three carbon. So first we're going to balance our cobalt and to do that, we're going to put a two here. So now we have two cobalt and we have two times three. So six nitrogen plus two, so eight nitrogen. And we have six Times three oxygen. So 18 oxygen. Now we're going to balance our carbon. So we're going to put a three here. So we have three times two nitrogen. So that's six plus two times three Nitrogen. So that's six. So we have 12 nitrogen And we have three Times four times 2 hydrogen. So we have 24 hydrogen And we have three carbon. We have three times three, so nine plus two times three times three. So We have 27 oxygen. And now we need to balance our nitrogen. So we're going to put a six in front of our ammonium nitrate. So we have six Plus six nitrogen, so we have 12 nitrogen. We have six times 4 hydrogen, So 24 hydrogen. We have six times three oxygen, plus three times three oxygen, So 27 oxygen. And now we are all balanced. So that is our final balanced chemical equation. Thank you for watching. Bye.