Skip to main content
Ch.22 - Organic Chemistry

Chapter 22, Problem 56d

Name each alkyne. d.

Verified Solution
Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
368
views
Was this helpful?

Video transcript

Hey everyone where asked which of the following is the correct name for the alkaline first. Let's go ahead and determine our route chain, which can also be called our parent chain. And this means it is our longest chain. So counting off we have and nine. It looks like we have a nine carbon chain. But let's go ahead and count it off going to the right straight away. So we have and eight. So we can see that this red numbering gives us only eight carbons. So this can't be our answer. So we can safely eliminate D. Since D tells us that our longest chain is an eight carbon chain due to that prefix of oct. Now why don't we number this in the reverse way? So Why didn't we remember this as 12345678 and nine. So the numbering in red would be incorrect. And the reason why is because Our al Qaeda here is listed at carbon # six. And we want our al Qaeda to have the lowest number possible since it takes priority. And with our blue lettering are al kind is written at carbon # three. And since we've recognized that carbon number three, we can also eliminate answer choice A. Since it tells us that our al Qaeda's at carbon number two. Now to look at our substitute wint, we can see that our substitution is at carbon # six and I'll go ahead and highlight it in pink. Now this is our substitute wint and we can see that we have a beautiful group so we can go ahead and eliminate answer choice B. Since this tells us that we have three different substitue ints and looking at carbon number six, we don't have an ethyl group and looking at carbon number seven, we do not have a dimethyl group. So our answer here is going to be C six Tribunal three non nine. Now, I hope that made sense and let us know if you have any questions.