Living organisms use energy from the metabolism of food to create an energy-rich molecule called adenosine triphosphate (ATP). The ATP acts as an energy source for a variety of reactions that the living organism must carry out to survive. ATP provides energy through its hydrolysis, which can be symbolized as follows: ATP(aq) + H₂O(l) → ADP(aq) + P_i(aq) ΔG°_rxn = -30.5 kJ where ADP represents adenosine diphosphate and P_i represents an inorganic phosphate group (such as HPO₄^2-). b. The free energy obtained from the oxidation (reaction with oxygen) of glucose (C₆H₁₂O₆) to form carbon dioxide and water can be used to re-form ATP by driving the given reaction in reverse. Calculate the standard free energy change for the oxidation of glucose and estimate the maximum number of moles of ATP that can be formed by the oxidation of one mole of glucose.

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Hi everyone here we have a question telling us that the following reaction shows the hydraulics sis of the denizen triphosphate. Where A. D. P. Stands for a denizen di phosphate MP stands for, or an organic phosphate groups such as h. p. 0. 4 2 http. Acquis plus H +20. Liquid forms a dentist scene. Di phosphate. Acquis plus an inorganic phosphate group. And the free energy is negative. 30.5 killed jules. A denizen triphosphate can be reformed from the free energy gained in the oxidation of glucose, which runs the above reaction in reverse in the oxidation of glucose, it reacts with oxygen to form carbon dioxide and water. What is the standard free energy change for the oxidation of glucose? How many moles of a denizen triphosphate can be produced at the highest possible rate from the oxidation of two moles of glucose. So first we need to calculate the free energy of the oxidation of glucose. So we have C6 H. 12 oh six plus six oxygen Forms six Carbon dioxide plus six water. So our change and free energy for the reaction equals the change in free energy of the product minus the change in free energy of the reactant. So our change in free energy equals six times negative 394.4 kg jewels. And this is a number that has to be looked up or found in your book plus six Times negative. 200, killer jewels minus One times negative, 910 .4 kg jewels Plus six times killer jewels. So our change in free energy is negative, 2878.6 kg drools. And now we need to calculate the moles of ATP per glucose molecule. So our free energy of glucose oxidation, divided by the free energy of ATP hydraulic sis equals negative 2878.6 kg rules, times two, Divided by negative 30 .5 Killed Jules Equals 189 moles of ATP reformed per glucose mole oxidized. And that is our final answer. Thank you for watching. Bye.

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Key Concepts

Adenosine Triphosphate (ATP)

Free Energy Change (ΔG)

Oxidation of Glucose