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Ch.19 - Free Energy & Thermodynamics

Chapter 19, Problem 64c

For each reaction, calculate ΔH°rxn, ΔS°rxn, and ΔG°rxn at 25 °C and state whether or not the reaction is spontaneous. If the reaction is not spontaneous, would a change in temperature make it spontaneous? If so, should the temperature be raised or lowered from 25 °C? c. N2(g) + O2(g) → 2 NO(g)

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everyone. So I asked what is the standard change in entropy of their reaction? What is the standard change in entropy of the reaction in the standard changing gibbs. Free energy of the reaction or asked. Is the reaction spontaneous. If not we're changing the temperature. Make it spontaneous. And if so should it be increased or decreased? We call that delta G. Other reaction. He goes delta H. Other reaction minus T. Delta. S. Other reaction we need to first find delta. S. Or the reaction. And this is a song. The number of malls. I was delta S. M. Other products minuses. Some times in times Delta S. M. Other reactant. The doctor S. M. A. C. O. Eagles. 30 just four more times Calvin, delta S. M. 02. It was 205.2 joe's caramel times kelvin, delta S. M. F. C. 00. It's 53. Just promote thomas Calvin. So that's the s of the reaction. Is it going to malls F. C. L. O. Times 53 does promote times kelvin minus two malls. The L. I'm study that's primal Calvin. Just one more 02 times 205 point to promote times kelvin. That? S the reaction It's making 0.159 killed for kelvin. Now I need to find delta H. Of the reaction. That's H. Other reaction it was a. Some comes in delta H. F. Other products. This is sam times in times delta H. F. Other reactant. The delta H. F. L. C. O. zero Delta H. F. 020 doctor H. F. C. O. Make it 237.9 joules per mole delta H. Other reaction? It's two molds. Oh, I was making 237 .9 Killed Jules Remote minus two malls. A. C. O. I'm zero kill goals for mom. That's one more 02 times zero kg per mole. The delta H of the reaction. It was made a 476 field goals and Delta G. Other reaction, It was mega 476 goals minus 25 Plus 273. -0.159. Tell jules Calvin for delta G. Of the reaction You get mega called jaws. Delta G. Other reaction is negative. So this is spontaneous. Thanks for watching my video and I hope it was helpful.
Related Practice
Textbook Question

For each reaction, calculate ΔH°rxn, ΔS°rxn, and ΔG°rxn at 25 °C and state whether or not the reaction is spontaneous. If the reaction is not spontaneous, would a change in temperature make it spontaneous? If so, should the temperature be raised or lowered from 25 °C? a. N2O4(g) → 2 NO2(g)

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Textbook Question

For each reaction, calculate ΔH°rxn, ΔS°rxn, and ΔG°rxn at 25 °C and state whether or not the reaction is spontaneous. If the reaction is not spontaneous, would a change in temperature make it spontaneous? If so, should the temperature be raised or lowered from 25 °C? d. N2(g) + 3 H2(g) → 2 NH3(g)

1011
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Textbook Question

For each reaction, calculate ΔH°rxn, ΔS°rxn, and ΔG°rxn at 25 °C and state whether or not the reaction is spontaneous. If the reaction is not spontaneous, would a change in temperature make it spontaneous? If so, should the temperature be raised or lowered from 25 °C? a. 2 CH4(g) → C2H6(g) + H2(g)

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Textbook Question

For each reaction, calculate ΔH°rxn, ΔS°rxn, and ΔG°rxn at 25 °C and state whether or not the reaction is spontaneous. If the reaction is not spontaneous, would a change in temperature make it spontaneous? If so, should the temperature be raised or lowered from 25 °C? d. 2 KClO3(s) → 2 KCl(s) + 3 O2( g)

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Textbook Question

Use standard free energies of formation to calculate ΔG° at 25 °C for each reaction in Problem 61. How do the values of ΔG° calculated this way compare to those calculated from ΔH° and ΔS°? Which of the two methods could be used to determine how ΔG° changes with temperature?

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Textbook Question

Consider the reaction: 2 NO(g) + O2(g) → 2 NO2(g) Estimate ΔG° for this reaction at each temperature and predict whether or not the reaction is spontaneous. (Assume that ΔH° and ΔS° do not change too much within the given temperature range.) b. 715 K

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