Write chemical equations and corresponding equilibrium expressions for each of the two ionization steps of carbonic acid.

Video transcript

Hey everyone, we're asked to consider the di protic acid, oxalic acid and they want us to identify the chemical equations and the equilibrium expressions for each immunization step. Starting with our first ionization step, we have oxalic acid which has A formula of C two H 204. We react this with water and we end up with hydrogen oxalate, which has a formula of C two H 04 minus. So we removed one hydrogen and hydro ni um ions. Our equilibrium expression for this. We can label as K. A. one since it's our first ionization step and this is going to be our products over our reactant and we don't include our water here since it's a liquid. Moving on to our next ionization step, we're going to take our hydrogen oxalate, which is C two H 04 minus and we're going to react this with water. Our products are going to be our oxalate ion, which is C 2042 minus since we removed that hydrogen and again our hydro ni um ion. Our equilibrium expression is going to be labeled as KA two. Since this is our second ionization step and again it's going to be our products over our reactant. So I hope this made sense. And let us know if you have any questions