Consider the reaction: 2 H₂O₂(aq) → 2 H₂O(l ) + O₂( g) The graph shows the concentration of H₂O₂ as a function of time. Use the graph to calculate each quantity: d. If the initial volume of the H₂O₂ is 1.5 L, what total amount of O₂ (in moles) is formed in the first 50 s of reaction?

Video transcript

Hey everyone in this example it says that the kinetic data for the reaction of to a to form B plus C is given below. And we need to calculate the moles of B Formed in the 1st 40 seconds of the reaction given that there is initially to leaders of our reactant. A. So our first step is to think of our change of concentration of our react in a At the given time frame which according to the prompt, should be at the 1st 40 seconds of the reaction. So according to the data, we would take that the change in concentration of a at our final time which should be 40 seconds subtracted from our change in concentration of a at its initial time being at zero seconds. According to the prompt is going to equal We have at seconds in the picture that they give us 0.674 as our Mueller concentration Subtracted from the time at or the concentration at zero seconds which is given in the picture as .1.500 moller. And so this difference gives us a value equal to negative 0.8- Mohler as our change in concentration of our reactant. A But the prompt wants us to calculate moles of B. So we're going to use this information that we just calculated to find the change in our concentration of reactant or our product rather be and this should be equal to our change in concentration of our react in A. Which according to our given equation has a coefficient of two. So we're going to say that this coefficient should be in the in the denominator. So we would make this a fraction being one half. And this is going to be negative since A. Is a reactant. So we're losing this to form our product. And so this should be equal to negative one half, multiplied by its change in concentration, which we just found above as negative 0.826 molar. So multiplying this out, we're going to get a value equal to 0.413 molar as our change in concentration of our product B. Now we want to recall that we can interpret units of polarity as moles divided by leaders. And so we can say that since this reaction happens in a two liter vessel filled with RV agent A. We would go ahead and find moles of our product B. By taking The change in our product Polarity which we found as .413 Molar. But we're going to interpret this as moles per leader. Since we know that that is equivalent to polarity. And we're going to multiply this by our two leaders of our reactant. And so this allows us to cancel out our units of leaders leaving us with moles, which is what we want. So this is going to give us a value of 0.826 moles of our product B. That is formed. And this is for the 1st 40 seconds of our reaction. So what's highlighted in yellow here is our final answer for the moles of B that is formed. If you have any questions, please leave them down below, and I will see everyone in the next practice video.