An aqueous solution contains 25% HCl by mass. Calculate the molality and mole fraction of the solution.

Video transcript

everyone. So I asked how could the morality And more fraction of an aqueous solution. That is 12.5% sodium hydroxide by mass. We call that the morality. It's moles of solute. Bye bye kilograms of solvent. And the more fraction is there more of the same by by the the total number of malls in the solution. We're gonna assume we have 100 g solution for the mask. A sliding hydroxide. 0.125. I was 100 g. We get 12.5 grounds. So then for the mask of H two L. Get 100 g -12.5. And that gives us 87.5 g nineties calculate the number of moles of sodium hydroxide in H 20. With 12.5 g of sodium hydroxide. And in one mall I'll see him hydroxide. And the molar mass. I get 22.990 g plus 15. g. 1.008g. I guess. That's 40 g. I get 0.3125 goals upsetting hydroxide. There were 87.5 g H 20. And in one mold of H 20. We have the molar mass And this too was 1. Plus 15. Get 18.02 g. This gives us 4.856 Balls Up H 20. And I can calculate the wall fraction. It's gonna be the mole fraction of sodium hydroxide equals the number of moles of sodium hydroxide by by the number of moles of sodium hydroxide. That's the number of moles of H 20. I get 0.3125 balls five x 0.3125 goals. That's 4.54.856 balls, 0.0605. Now, for the morality of setting hydroxide, get the mall's hot outside. Bye bye kilograms Of H 20. We need to first convert the mass of H20 into kg, g and one kg equals 1000 g. You get 0.0875 kg. Medical practices to the equation for the lady. A setting hydroxide. I'm going to get 0.3125 bones. About 0.0875 kilograms. Let me get 3.57. Thanks for watching my video and I hope it was helpful.