Complete and balance each gas-evolution equation. a. HNO 3 (aq) + Na 2 SO 3 (aq) →

Welcome back everyone. The reaction between Aquarius hydrogen fluoride and Aquarius strontium sulfide. It produces a gas right? The balanced equation for this gas evolution reaction were given our reactant hydrogen fluoride and strontium sulfide. They're both Aquarius. And in order to predict our products, we're going to recognize that this is going to be a double replacement for displacement reaction. So recall that in a double replacement reaction, our cat ions will combine with one another. Or sorry, our captain will combine with an ion. So in the case of our H plus kati on, it's going to combine with our cell fight an ion. Recall that sulfide as a poly atomic ion where we'll have the two minus an ion charge and our hydrogen ion is a H plus catalon. And that's because hydrogen we recall is in group one A on the periodic table and any atom in group one A will form a plus one ion charge. Next we'll combine our fluoride. An ion with our strontium caddy on where we recall because florian is also a group seven A ion, it's going to form a minus one charge. So we would have f minus one and strong Tm. We recognize as a group to a on the periodic table and will form a two plus charge as a caddy on. So now combining our ions will form our products with the combination of H plus and S. +032 will have a church sub two since hydrogen will get the charge of our cell fight an ion and then we'll have S. +03 because sulfite will get the charge of our hydrogen ion caddy on this is going to be our first Aquarius product as sulfurous acid. And then for our second product, we're going to form the combination of our fluoride an ion and our strontium carry on, which is going to be S. R. Sub one, since strontium will get the anti on charge of flooring as one and then F sub two since flooring will get the caddy on charge on strontium. And this is also an Aquarius product because it's going to dissociate into it's ions. Now for our sulfurous acid product, we want to recognize that sulfurous acid is actually thermo dynamically and stable in this state. And so because it is well known to be a thermo dynamically unstable product here, we're going to have to recall that it's going to spontaneously decompose into water and sulfur dioxide gas where it would be more stable since these products have lower energy than sulfurous acid. So we're going to need to also make sure that our reaction is balanced with these products. And if we recognize that on the product side, we have two moles of hydrogen and two moles of flooring, we're going to need that on the reactant side by placing a coefficient of two in front of our hydrogen fluoride, which also will give us two moles of hydrogen and two moles of flooring. So now with this coefficient added and with knowing that we need to spontaneously decomposed are sulfurous acid into water and sulfur dioxide gas. That's also going to help us answer this prompt since we need a gaseous product. So rewriting our entire equation, what we should have is two moles of hydrogen fluoride Reacting with one mole of strontium sulfide, which will produce water plus sulfur dioxide gas, plus our strontium fluoride product that is Aquarius. And this entire equation with our coefficient is going to complete this example as our final answer for our bounced reaction and our gaseous product sulfurous acid. I hope everything I reviewed was clear. If you have any questions, please leave them down below and I'll see everyone in the next practice video.

Ch.5 - Introduction to Solutions and Aqueous Solutions

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Tro 5th Edition

Ch.5 - Introduction to Solutions and Aqueous Solutions

Problem 60a

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Chapter 5, Problem 60a

Complete and balance each gas-evolution equation. a. HNO₃(aq) + Na₂SO₃(aq) →

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Identify the reactants: HNO_3 (aq) and Na_2SO_3 (aq).

Determine the products: The reaction between an acid (HNO_3) and a sulfite (Na_2SO_3) typically produces a salt (NaNO_3), water (H_2O), and sulfur dioxide gas (SO_2).

Write the unbalanced chemical equation: HNO_3 (aq) + Na_2SO_3 (aq) \rightarrow NaNO_3 (aq) + H_2O (l) + SO_2 (g).

Balance the equation: Start by balancing the number of sodium (Na) atoms, then balance the nitrogen (N) atoms, followed by the oxygen (O) and hydrogen (H) atoms.

Verify that the number of atoms for each element is equal on both sides of the equation to ensure it is balanced.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Gas-Evolution Reactions

Gas-evolution reactions are chemical reactions that produce a gas as one of the products. These reactions often involve the combination of an acid with a carbonate, sulfite, or other compounds that release gas when they react. Understanding the nature of the reactants and the expected gas products is crucial for predicting the outcome of these reactions.

Balancing Chemical Equations

Balancing chemical equations is the process of ensuring that the number of atoms for each element is the same on both sides of the equation. This is achieved by adjusting the coefficients of the reactants and products. A balanced equation reflects the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.

Acid-Base Reactions

Acid-base reactions involve the transfer of protons (H⁺ ions) between reactants. In the context of the given equation, nitric acid (HNO3) acts as an acid, while sodium sulfite (Na2SO3) can act as a base. Recognizing the roles of acids and bases in a reaction helps in predicting the products formed, including any gases that may evolve.