Complete and balance each acid–base equation. a. H 2 SO 4 (aq) + Ca(OH) 2 (aq) → b. HClO 4 (aq) + KOH(aq) → c. H 2 SO 4 (aq) + NaOH(aq) →

Hey everyone. So I asked predicted products of the following asset based reaction and write a balanced chemical equation. Let's look at each reactor. We have nitrous acid H. n. 0. 2 and it's going to associate to give us each plus and N. 02 minus casting hydroxide. It's gonna give us the a. two plus and O. H minus. This is we have 20. H. Over here we need to put it in front of O. H. Minus. And this is a double displacement reaction. We have to gun pounds reacting so we can switch the ions to form new products. So if we switch we're gonna have a church plus plus O. H minus, we're just gonna yield water. They were going to see a 2-plus And n. 0. 2 -. We're just going to get calcium nitrate. And this is Aquarius because nitrates are soluble, we're gonna have nitrous acid plus calcium hydroxide. And it's gonna get water plus calcium nitrate. So to balance this we need to look at all the elements on both sides. We have a hydrogen, a nitrogen oxygen and a calcium on both sides. We have two plus one for a total of three hydrogen. Over here We have one nitrogen. We have two plus 24 total four oxygen over here we have one cassie. Um Over here we may have to hydrogen over here to national over here two times 2 is four Plus one for a total five oxygen over here and one calcium over here since we have one nation on the acting side but two on the product side. you can also buy two over here and get to, you can put it to in front of nitrous acid and now we have to Plus two for total four hydrogen over here, They can put a two in front of H 20. to get four hydrogen over here And over here we have two times two, which is four plus super total of six oxygen over here And here we have two plus two times two, which is +44 total six auction over here. So now this is balance. So for the equation we're gonna have to nitrous acid plus calcium hydroxide And it's Gonna Yolk to H 20. Like what? Plus calcium nitrate. Thanks for watching my video and I hope it was helpful.

Ch.5 - Introduction to Solutions and Aqueous Solutions

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Tro 5th Edition

Ch.5 - Introduction to Solutions and Aqueous Solutions

Problem 53

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Chapter 5, Problem 53

Complete and balance each acid–base equation.
a. H₂SO₄(aq) + Ca(OH)₂(aq) →
b. HClO₄(aq) + KOH(aq) →
c. H₂SO₄(aq) + NaOH(aq) →

Verified step by step guidance

Identify the type of reaction: This is an acid-base neutralization reaction where sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH).

Write the unbalanced chemical equation: H2SO4(aq) + NaOH(aq) → Na2SO4(aq) + H2O(l).

Balance the equation by ensuring the number of atoms of each element is the same on both sides. Start by balancing the sodium (Na) atoms.

Since H2SO4 has two acidic hydrogens, it will react with two NaOH molecules. Adjust the coefficients: H2SO4(aq) + 2 NaOH(aq) → Na2SO4(aq) + 2 H2O(l).

Verify the balance: Check that the number of each type of atom (H, S, O, Na) is equal on both sides of the equation.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Acid-Base Reactions

Acid-base reactions involve the transfer of protons (H+) between reactants. In this context, sulfuric acid (H2SO4) acts as an acid, donating protons, while sodium hydroxide (NaOH) serves as a base, accepting protons. The result is the formation of water and a salt, showcasing the neutralization process typical of acid-base reactions.

Balancing Chemical Equations

Balancing chemical equations is essential to ensure that the number of atoms for each element is the same on both sides of the equation. This reflects the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. In the given equation, coefficients are adjusted to achieve balance, particularly for the products formed.

Strong Acids and Bases

Strong acids and bases completely dissociate in aqueous solutions. H2SO4 is a strong acid that dissociates into H+ and HSO4- ions, while NaOH is a strong base that dissociates into Na+ and OH- ions. Understanding their complete dissociation is crucial for predicting the products of the reaction and for balancing the equation accurately.

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A 25.00-mL sample of an unknown HClO₄ solution requires titration with 22.62 mL of 0.2000 M NaOH to reach the equivalence point. What is the concentration of the unknown HClO₄ solution? The neutralization reaction is HClO₄(aq) + NaOH(aq) → H₂O(l) + NaClO₄(aq)

Complete and balance each acid–base equation. a. H2SO4(aq) + Ca(OH)2(aq) →b. HClO4(aq) + KOH(aq) →c. H2SO4(aq) + NaOH(aq) →

Verified Solution

Key Concepts

Acid-Base Reactions

Balancing Chemical Equations

Strong Acids and Bases

Complete and balance each acid–base equation.
a. H₂SO₄(aq) + Ca(OH)₂(aq) →
b. HClO₄(aq) + KOH(aq) →
c. H₂SO₄(aq) + NaOH(aq) →