Rutherfordium-257 was synthesized by bombarding Cf-249 with C-12. Write the nuclear equation for this reaction.

Video transcript

Hey everyone, we're asked what is the nuclear equation for the reaction? Where burke helium 2 51 was bombarded with carbon 12 to produce Lawrence idiom to 60 First. Let's go ahead and write out what we know. We have burke helium 251 And looking at our periodic table. This has an atomic number of 97 Plus Our Carbon 12, which has an atomic number of six. This produced Lawrence any um to 60, which has an atomic number of 103 plus a missing particle, which we can label as X for now with an atomic number of Z and an atomic mass of a 1st. Let's go ahead and solve for a We can go ahead and balance out our mass numbers and we have our 251 from our break helium plus 12 from our carbon. This is going to be equal to 260 plus a Solving for a we end up with a value of three. Now let's go ahead and solve for R. Z. Looking at our Z, we have 97 from our perky liam plus six from our carbon, which will get us to 103 plus Z. And it looks like Z comes up to zero. So it looks like our missing particle is going to be three neutrons. So I hope this made sense. And let us know if you have any questions