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Ch.21 - Radioactivity & Nuclear Chemistry

Chapter 21, Problem 37c

Determine whether or not each nuclide is likely to be stable. State your reasons. c. Co-51

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Hey everyone, we're asked to predict whether the isotope, Nickel 53 is stable or not. Looking at our periodic table, We find that Nickel has an atomic number of 28. Now we've learned that the stability of an isotope depends on our neutron to proton ratio. And in this case since our atomic number is in between and 40 Then R. N. oversee ratio must be equal to 1.25 in order to be considered stable. So let's go ahead and calculate our N oversee ratio. To calculate this, we can go ahead and calculate our neutrons by taking our A and subtracting R. Z. And then we'll divide everything by RZ. So plugging in our values, our a being our atomic mass, we have 53 -28 which is R. Z. Dividing everything by 28. Now, this will get us to a value of 0.89. As we can see this is less than our 1.25, which determines whether or not our isotope is stable. So, Nickel 53 is going to be not stable. So I hope this made sense. And let us know if you have any questions