- Ch.1 - Matter, Measurement & Problem Solving101
- Ch.2 - Atoms & Elements96
- Ch.3 - Molecules and Compounds118
- Ch.4 - Chemical Reactions and Chemical Quantities49
- Ch.5 - Introduction to Solutions and Aqueous Solutions78
- Ch.6 - Gases98
- Ch.7 - Thermochemistry83
- Ch.8 - The Quantum-Mechanical Model of the Atom49
- Ch.9 - Periodic Properties of the Elements71
- Ch.10 - Chemical Bonding I: The Lewis Model80
- Ch.11 - Chemical Bonding II: Molecular Shapes, VSEPR & MO Theory79
- Ch.12 - Liquids, Solids & Intermolecular Forces38
- Ch.13 - Solids & Modern Materials35
- Ch.14 - Solutions66
- Ch.15 - Chemical Kinetics83
- Ch.16 - Chemical Equilibrium52
- Ch.17 - Acids and Bases109
- Ch.18 - Aqueous Ionic Equilibrium128
- Ch.19 - Free Energy & Thermodynamics72
- Ch.20 - Electrochemistry87
- Ch.21 - Radioactivity & Nuclear Chemistry49
- Ch.22 - Organic Chemistry139
Chapter 19, Problem 69b
Consider the sublimation of iodine at 25.0 °C : I2(s) → I2( g) b. Find ΔG°rxn at 25.0 °C under the following nonstandard conditions: i. PI2 = 1.00 mmHg ii. PI2 = 0.100 mmHg
Video transcript
Use standard free energies of formation to calculate ΔG° at 25 °C for each reaction in Problem 61. How do the values of ΔG° calculated this way compare to those calculated from ΔH° and ΔS°? Which of the two methods could be used to determine how ΔG° changes with temperature?
Consider the reaction: 2 NO(g) + O2(g) → 2 NO2(g) Estimate ΔG° for this reaction at each temperature and predict whether or not the reaction is spontaneous. (Assume that ΔH° and ΔS° do not change too much within the given temperature range.) b. 715 K
Determine ΔG° for the reaction: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) Use the following reactions with known ΔG°rxn values: 2 Fe(s) + 3 2 O2(g) → Fe2O3(s) ΔG°rxn = -742.2 kJ CO( g) + 1 2 O2( g) → CO2( g) ΔG°rxn = -257.2 kJ
Consider the sublimation of iodine at 25.0 °C : I2(s) → I2( g) c. Explain why iodine spontaneously sublimes in open air at 25.0 °C
Consider the evaporation of methanol at 25.0 °C : CH3OH(l) → CH3OH(g) a. Find ΔG° r at 25.0 °C.
Consider the evaporation of methanol at 25.0 °C : CH3OH(l) → CH3OH(g) b. Find ΔG r at 25.0 °C under the following nonstandard conditions: i. PCH3OH = 150.0 mmHg ii. PCH3OH = 100.0 mmHg iii. PCH3OH = 10.0 mmHg