Skip to main content
Ch.11 - Chemical Bonding II: Molecular Shapes, VSEPR & MO Theory
Chapter 11, Problem 53c

The valence electron configurations of several atoms are shown here. How many bonds can each atom make without hybridization? c. F 2s22p5

Verified Solution

Video duration:
1m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Valence Electrons

Valence electrons are the outermost electrons of an atom and are crucial in determining how an atom can bond with others. The number of valence electrons influences an atom's reactivity and the types of bonds it can form. For example, fluorine (F) has seven valence electrons, which allows it to form one bond to achieve a stable octet configuration.
Recommended video:
Guided course
02:12
Transition Metals Valence Electrons

Bonding Capacity

Bonding capacity refers to the maximum number of bonds an atom can form based on its valence electron configuration. Atoms tend to form bonds to achieve a full outer shell, typically following the octet rule. In the case of fluorine, with its configuration of 2s²2p⁵, it can form one bond by sharing one of its unpaired electrons.
Recommended video:
Guided course
02:19
Heat Capacity

Hybridization

Hybridization is a concept in chemistry that describes the mixing of atomic orbitals to form new hybrid orbitals, which can influence the geometry and bonding of molecules. However, the question specifies 'without hybridization,' meaning we consider the atom's original atomic orbitals. For fluorine, without hybridization, it utilizes its existing p orbitals to form bonds.
Recommended video:
Guided course
00:51
Hybridization