Skip to main content
Ch.5 - Gases
Chapter 5, Problem 86

Calculate the ratio of effusion rates for Ar and Kr.

Verified Solution

Video duration:
1m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Graham's Law of Effusion

Graham's Law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. This means that lighter gases effuse faster than heavier gases. The formula can be expressed as (Rate1/Rate2) = √(Molar Mass2/Molar Mass1), allowing for the comparison of effusion rates between two different gases.
Recommended video:
Guided course
01:14
Graham's Law of Effusion

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is a critical factor in calculating effusion rates, as it directly influences the speed at which a gas can escape through a small opening. For argon (Ar), the molar mass is approximately 40 g/mol, while for krypton (Kr), it is about 84 g/mol.
Recommended video:
Guided course
02:11
Molar Mass Concept

Effusion

Effusion is the process by which gas molecules escape from a container through a tiny opening into a vacuum or lower pressure area. The rate of effusion is influenced by factors such as temperature and the size of the gas molecules. Understanding effusion is essential for applying Graham's Law and comparing the behavior of different gases under similar conditions.
Recommended video:
Guided course
01:31
Effusion Rate Example