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Ch.5 - Gases

Chapter 5, Problem 34

A syringe containing 1.55 mL of oxygen gas is cooled from 95.3 °C to 0.0 °C. What is the final volume of oxygen gas?

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Welcome back everyone to another video, a sealed container containing 5.52 mL of oxygen gas is cooled from 45.8 °C to 0.0 °C. What is the final volume of oxygen gas we're given for answer choices. A 4.73 B 2.52 C 3.47 in the 7.34 all of them are given in milliliters. Let's solve this problem. Let's understand that we are dealing with the ideal gas law which states that PV equals NRC. And immediately we want to identify which variables are changing. The problem states that we have exactly the same sample of oxygen gas. So the number of moles remains constant. There's no mention regarding pressure. So pressure is also constant as a result, what's changing is our temperature? And we are also changing volume, which means that if we rearrange our formula, the ratio V divided by T becomes NR divided by P. And we noticed that on the right hand side, all of the three variables are constants. Therefore, we have V over T being a constant. So for two different conditions, we have V one divided by T one is equal to V two divided by T two. What is the final volume? Well, we can rearrange the formula and state that the final volume B two is simply V one divided by T one multiplied by T two. Now let's substitute the givens V one is our initial volume which corresponds to 5.52 mL. C one is our initial temperature from means initial. So we're taking 45.8 °C, converting that into Kelvin well done. And now finally, we want to multiply by temperature two, the final temperature would be zero °C. And once again, we need to perform a conversion to Kelvin. Now we calculate the result and we end up with 4.73 mL. That's the final volume of oxygen gas. Let's identify the correct answer, which is in this case, option, a 4.73 mL. Thank you for watching.