Predict a likely mode of decay for each unstable nuclide. b. Ru-90 c. P-27 d. Sn-100
Ch.20 - Radioactivity and Nuclear Chemistry
Chapter 20, Problem 44a,b
Which nuclide in each pair would you expect to have the longer half-life? a. Cs-149 or Cs-139 b. Fe-45 or Fe-52
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Half-Life
Half-life is the time required for half of the radioactive nuclei in a sample to decay. It is a key concept in nuclear chemistry and helps in understanding the stability of isotopes. A longer half-life indicates a more stable nuclide, as it decays more slowly compared to those with shorter half-lives.
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Radioactive Decay
Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. This can occur in various forms, including alpha, beta, and gamma decay. The type of decay and the energy released can influence the half-life of a nuclide, affecting its stability and longevity.
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Nuclear Stability
Nuclear stability refers to the tendency of a nucleus to remain intact without undergoing radioactive decay. Factors influencing stability include the ratio of neutrons to protons and the overall binding energy of the nucleus. Generally, isotopes with a balanced neutron-to-proton ratio are more stable and exhibit longer half-lives.
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Related Practice
Textbook Question
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Textbook Question
Predict a likely mode of decay for each unstable nuclide. a. Sb-132 b. Te-139 d. Ba-123
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Textbook Question
Determine whether or not each nuclide is likely to be stable. State your reasons. a. Mg-26 b. Ne-25 c. Co-51
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Textbook Question
Write the nuclear equation for the most likely mode of decay for each unstable nuclide. a. Ru-114 c. Zn-58 d. Ne-31
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Textbook Question
Write a nuclear equation for the indicated decay of each nuclide. a. Po-210 (alpha) b. Ac-227 (beta)
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Open Question
Complete each nuclear equation and calculate the energy change (in J/mol of reactant) associated with each (Al-27 = 26.981538 amu, Am-241 = 241.056822 amu, He-4 = 4.002603 amu, Np-237 = 237.048166 amu, P-30 = 29.981801 amu, S-32 = 31.972071 amu, and Si-29 = 28.976495 amu).
b. 3216S + ______ → 2914Si + 42He
c. 24195Am → 23793Np + _____