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Ch.19 - Electrochemistry
Chapter 19, Problem 90

Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. Label the anode and cathode, indicate the direction of electron flow, and write an equation for the half-reaction occurring at each electrode. What minimum voltage is necessary to drive the reaction?

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electrolytic Cell

An electrolytic cell is a device that uses electrical energy to drive a non-spontaneous chemical reaction. It consists of two electrodes: the anode, where oxidation occurs, and the cathode, where reduction takes place. In this cell, an external power source provides the necessary voltage to facilitate the movement of electrons, allowing the desired chemical transformations to occur.
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Half-Reactions

Half-reactions represent the individual oxidation and reduction processes occurring in an electrochemical cell. In this context, the reduction half-reaction involves Mn2+ gaining electrons to form solid Mn, while the oxidation half-reaction involves Sn losing electrons to form Sn2+. Writing these half-reactions helps in understanding the electron transfer and balancing the overall redox reaction.
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Minimum Voltage (Electrolysis)

The minimum voltage required to drive an electrolytic reaction is known as the cell potential or decomposition potential. This voltage must overcome the inherent energy barriers of the reactions occurring at the electrodes. It can be calculated using the standard reduction potentials of the half-reactions, and it is essential for ensuring that the desired redox processes occur efficiently in the electrolytic cell.
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