Consider the evaporation of methanol at 25.0 °C : CH3OH(l) → CH3OH(g) a. Find ΔG° r at 25.0 °C.

Video transcript

Hello everyone. Today we have the falling problem. Consider the evaporation of methanol at 25 °C. And we are being tasked to find the change and give us free energy for the reaction at 25 °C. So we can do that with the following equation, I think gives free energy for the reaction is equal to the sum of the chain is for energy of our products subtracted by that of the reactives. So if we use the standard table of values for given gives free energies, we can note that for methanol which is our product will be negative 166.6 kilojoules per mole, we subtract that from the gives free energy of our methanol and the liquid form which would be negative 1 62.3 kilojoules per mole. And in doing that, we get a gibbs free energy for the reaction that is equal to 4.300 kilojoules Perel as our final answer or answer twice. D overall, I hope is helped. And until next time