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Ch.17 - Aqueous Ionic Equilibrium

Chapter 17, Problem 99c

Determine if each compound is more soluble in acidic solution than it is in pure water. Explain. c. AgCl

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All right. Hi everyone. So for this question, let's go ahead and determine if each compound is more soluble in acidic solution than it is in pure water. Explain. Now, here our compound is a GCL otherwise known as silver chloride. Now, here we have four different answer choices labeled A through D discussing whether or not silver chloride is more soluble in acidic solution or pure water. Now, notably the explanations provided, discuss whether or not silver chloride is a neutral, a basic or an acidic salt. Now recall that salts are ionic compounds that compose or are composed of a cion with a positive charge and an anion with a negative charge. So based on certain criteria, we can decide whether or not a given salt is acidic, basic or neutral. Now recall the basic salts are going to be more soluble in acidic solutions whereas acidic salts are most soluble in basic solutions. Now, by contrast, a neutral salt would be most soluble in pure water due to its neutrality. So now let's consider the specific criteria or silver chloride. Now, to determine whether or not silver chloride is acidic, basic or neutral, there are certain criteria depending on the cion and the anion separately. Now, starting with the cat island, it's very common that the cion is a metal. So in this case, we have to diff differentiate between a transition metal and a main group metal. In the case of a transition metal, a given cion is considered acidic if the charge if is positive two or more or higher. Now, by contrast, if you have a main group metal, the net cion is considered to be acidic. If the charge is positive three or more, if the charge is less than positive two or positive three respectively, then that cion is considered neutral. Now, in the case of silver chloride, silver is a transition metal with a charge of positive one. So according to the criteria previously described silver is a transition metal that has a charge that is a less than positive too, which means it's silver or cion is neutral in the case of silver chloride. So that settles the Canion. Now, let's discuss the anion in the case of an anion to determine whether or not it is acidic, basic or neutral, we have to consider what species forms. After adding a proton or h positive to the anion itself. This creates two different possibilities. When a proton is added to an anion, we can produce either a weak acid or a strong acid. If a weak acid is produced, then the negative ion or the anion is considered basic. Whereas if a strong acid is created that anion is neutral, right? This is because strong acids produce weak conjugate bases and vice versa. So in this case, our anion is chloride or cl negative. So when we add a proton to chloride, the resulting species is HC. Now because HCO is a remarkably strong acid, the conjugate base, in this case, chloride is relatively weak. In other words, it is neutral. So the reason why silver chloride is a neutral salt is because it is the combination of a neutral cion and a neutral anion. And so because it is a neutral salt, it would be more soluble in pure water because neither the cion or the anion will react in acidic conditions. This means that our answer is option c in the multiple choice, sulfur chloride is more soluble in pure water than in acidic solution because it is a neutral salt and there you have it. So with that being said, if you watched until the end of this video, thank you so very much for watching. And I hope you found this helpful.