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Ch.15 - Chemical Equilibrium
Chapter 15, Problem 6

Consider the reaction: CO(g) + H2O(g) ⇌ CO2(g) + H2(g) Kp = 0.0611 at 2000 K. A reaction mixture initially contains a CO partial pressure of 1344 torr and a H2O partial pressure of 1766 torr at 2000 K. Calculate the equilibrium partial pressures of each of the products.

Verified step by step guidance
1
Convert the initial partial pressures from torr to atm by dividing each by 760, since 1 atm = 760 torr.
Set up an ICE (Initial, Change, Equilibrium) table to track the changes in partial pressures of each species. Let the change in pressure for CO and H2O be \(-x\), and for CO2 and H2 be \(+x\).
Write the expression for the equilibrium constant \(K_p\) in terms of partial pressures: \(K_p = \frac{P_{CO_2} \cdot P_{H_2}}{P_{CO} \cdot P_{H_2O}}\).
Substitute the equilibrium expressions from the ICE table into the \(K_p\) expression and solve for \(x\).
Calculate the equilibrium partial pressures by substituting \(x\) back into the expressions for each species: \(P_{CO} = P_{CO, initial} - x\), \(P_{H_2O} = P_{H_2O, initial} - x\), \(P_{CO_2} = x\), and \(P_{H_2} = x\).