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Ch.14 - Chemical Kinetics
Chapter 14, Problem 77b

Consider this three-step mechanism for a reaction:
Cl2 (g) k1⇌k2 2 Cl (g) Fast
Cl (g) + CHCl3 (g) →k3 HCl (g) + CCl3 (g) Slow
Cl (g) + CCl3 (g) →k4 CCl4 (g) Fast
b. Identify the intermediates in the mechanism.

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Intermediates are species that are produced in one step of a reaction mechanism and consumed in a subsequent step.
Examine each step of the mechanism to identify species that are not present in the overall balanced equation.
In the first step, Cl<sub>2</sub> dissociates into 2 Cl atoms.
In the second step, Cl reacts with CHCl<sub>3</sub> to form HCl and CCl<sub>3</sub>.
In the third step, Cl reacts with CCl<sub>3</sub> to form CCl<sub>4</sub>.

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