For a solution prepared by dissolving 28.4 g of glucose (C6H12O6) in 355 g of water with a final volume of 378 mL, calculate the concentration in each unit: a. molarity, b. molality, c. percent by mass, d. mole fraction, e. mole percent.

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Calculate the molar mass of glucose (C_6H_{12}O_6) by adding the atomic masses of all atoms in the formula.

Convert the mass of glucose (28.4 g) to moles using its molar mass.

For molarity (a), divide the moles of glucose by the volume of the solution in liters (convert 378 mL to liters).

For molality (b), divide the moles of glucose by the mass of the solvent (water) in kilograms (convert 355 g to kg).

For percent by mass (c), divide the mass of glucose by the total mass of the solution (glucose + water) and multiply by 100 to get the percentage.

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