The compounds below are paired with a type of bonding. Which type of bonding is incorrectly classified? (LO 7.5) (a) Rb2O (polar covalent) (b) SO2 (polar covalent) (c) O3 (nonpolar covalent) (d) KBr (ionic) (e) HF (polar covalent)

Video transcript

Welcome back everyone. We're told that the following compounds are listed with a type of bond and we need to identify the incorrect pairing. So we're going to begin with option a where we have sodium chloride. We're told that it's an ionic bond between these two atoms and we want to analyze each atom. So we begin with sodium, which we recognize is in group one a. On our periodic table and based on its position is going to be considered a medal. It's bonded with Chlorine, which we would recognize in group seven a. Are halogen group on the periodic table, meaning that chlorine is considered a non metal. And based on this pairing of metal and nonmetal, we would agree that this is going to be an ionic compound with an ionic bond between these two atoms. Moving on, we have in choice B. Our molecule of water. And sorry, we would rule out choice A. So in choice B we have water where we have hydrogen based on its position in group one A. It's the only exception being a nonmetal and it's bonded to oxygen where we would recognize oxygen Group six A of our periodic table, meaning oxygen is also a nonmetal because we have the pairing of two non metals. We would consider that this is going to be a covalin or molecular compound. And as far as polarity, we would recognize that oxygen being all the way on the far right in Group six A. On the periodic table will have a greater election negativity than oxygen, which is why we would label this as polar covalin. So so far we can also rule out Choice B. And now we would rule or focus on Choice C. Carbon tetrachloride, which is told to be non polar covalin bond between these two atoms. And so beginning with carbon, we would agree that because it's in Group four A. On the periodic table it's considered a non metal atom, Whereas it's bonded to chlorine, which is located in our Halogen Group seven a. And also considered a nonmetal. And because we see that carbon being in group for a incline being in Group seven a. Are groups that are close to one another on the periodic table, we have a very minimal election negativity difference. So we'll say minimal difference in electro negativity. And so therefore we would label this compound as non polar co violent for carbon tetrachloride. So we would also rule out Choice C. Because it is a correct pairing for the type of bond. And so now we have hydrochloric acid where we see that we have and we'll do the work here below hydrogen, which we agreed earlier is a non metal atom bonded to chlorine, which we agreed earlier is also a nonmetal. And because we would recognize that we have a very great difference in election negativity between hydrogen being in group one A. And chlorine being in Group seven A. On the periodic table, we would label this compound as therefore a polar covalin compound. And so we would look at choice D as a good prospect for an anti choice as an incorrect pairing. Moving onto choice E. We have calcium oxide and let's use the color blue still. So we have calcium oxide. We're told that it has an ionic bond. So beginning with calcium based on its position in Group two A of our periodic table, it's going to be considered a medal. It's bonded to oxygen, which as we stated, is a non metal in group six A. So a non metal bonded to a metal atom means that we're going to have an ionic compound. And this is a correct pairing here or sorry, an ionic compound. An ionic bond, meaning that this is a correct pairing. And we can rule out choice. Moving on to choice F. We have our adam for sorry. Our molecule for ammonia, where we would recognize that nitrogen based on its position in Group five A. On the periodic table is considered a nonmetal. It's bonded to hydrogen, which we would consider also a non metal. And we have the pairing of these two non metals, meaning that we have a Covalin compound. And as far as polarity, we recognized that nitrogen being in Group seven or sorry, in Group five A. As we stated, is going to create this great electro negativity difference between nitrogen and hydrogen, meaning that we would label this as a polar covalin bond between our nitrogen and hydrogen atoms. And so we would agree that choice was a correct pairing, and we can rule it out. And so in summary, we can confirm that the only incorrect pairing is hydrochloric acid being listed as a non polar covalin bond between the atoms hydrogen and chlorine, which we disagreed with, and confirmed that it should be a polar covalin bond based on that great election activity difference between hydrogen and chlorine on the periodic table. I hope that everything I went through is clear. If you have any questions, please leave them down below and I'll see everyone in the next practice video.