A flask containing 450 mL of 0.500 M HBr was accidentally knocked to the floor. How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation?

Video transcript

Hello everyone. So in this video we need to go ahead and calculate the mass of sodium carbonate required to completely neutralize the acid. So they give us the neutralization equation here. So go ahead and use it for our multiple ratios. Alright, so first we're given that we have 600 ml of this concentration of hcl. So that's how we'll start off our dimensional analysis. So again we're starting off with 600 ml of hcl. We want to convert our millions and are leaders. So we can go ahead and utilize our polarity. So convert our middle leaders and to leaders. And then we can go ahead and use our maturity as our second conversion factor. So let's go ahead and recall that capital M. So polarity is equal to most her leader. So then we have 0. moles of hcl for every one liter of solution. So so far we can see that our male leaders will cancel. Leaders will cancel. All right, So now we're stuck with here the moles of Hcl again, we need to go ahead and look for the moles of our N. A. To C. 03 are sodium carbonate. So now we can go ahead and do a multi mole ratio here. So you see from our reaction that's given to us in the problem that for every two moles of hcl We'll need one mole of sodium carbonate. Now you can see that the moles of Hcl will cancel. Now it says we need to calculate the mass and that's usually in the units of grams. How we can get that is by using the molar mass of sodium carbonate, which you can either find online calculator itself or it can be given to you by professor. So here what I have is that for every one mole of our sodium carbonates That equals to 105. g of sodium carbonate. Alright, now we can see that the moles of sodium carbonate. Well, council so putting this into my calculator, I'll get the numerical value of 9. and units being grams of sodium carbonates. So that's how much it takes to completely neutralize our hydrochloric acid here.