A compound with the formula XOCl2 reacts with water, yielding HCl and another acid H2XO3, which has two acidic hydrogens that react with NaOH. When 0.350 g of XOCl2 was added to 50.0 mL of water and the resultant solution was titrated, 96.1 mL of 0.1225 M NaOH was required to react with all the acid. (a) Write a balanced equation for the reaction of XOCl2 with H2O.

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Hey everyone, we're told when a substance with the formula XpR three reacts with water, hydrochloric acid and another acid, H three X. 03 are produced. H three X 03 also contains three acidic hydrogen that react with potassium hydroxide. After tight trading a solution made up of 3.67 g of XpR three and mL of water, it was discovered that 87.3 mL of 0.132 molar potassium hydroxide were needed to completely neutralize the acid for the reaction of XpR three with water. Right? A balanced equation. As we said, we had XPR three and this reacted with water. We produced our other acid which was given by H three X. 03 and hydro bro mc acid. So let's go ahead and balance this out. We first have to look at each side are reacting and our product side and count the number of atoms we have per element. So starting with our react inside. Looking at our X. We have one of X. Looking at our bro means we have three of grooming. Looking at our hydrogen, we have two and looking at our oxygen's, we have one. Now let's go ahead and move on to our product side again. Looking at our X. We have one of X. We have one of grooming, we have three of hydrogen and three of oxygen's first let's go ahead and balance out our bro means first we can do so by looking at our product side and if we add a coefficient of three prior to hydrochloric acid, we change our values of bromine to be three, but we also change the values of hydrogen to be six. Now let's go ahead and balance out our react inside. It seems like we only need to balance out our hydrogen and our oxygen's. So if we add that coefficient of three prior to water, we end up with six of hydrogen and three of oxygen and looking at both sides, we can see that everything is completely balanced out. So this is going to be our final answer. Now. I hope that made sense and let us know if you have any questions.

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Key Concepts

Balancing Chemical Equations

Acid-Base Reactions

Stoichiometry