The following diagram represents the reaction of A₂ (red spheres) with B₂ (blue spheres):

(a) Write a balanced equation for the reaction, and identify the limiting reactant. (b) How many moles of product can be made from 1.0 mol of A₂ and 1.0 mol of B₂?

Video transcript

Welcome back everyone. We're told that the image below shows the reaction between a green spheres and B. Two orange spheres to form A. B. Three, identify the limiting reagent and to calculate the moles of a. B three formed using one mole of A and one mole of B. Two. So our first step is to write out a chemical equation. We have our re agents A which are green spheres. So we use the color green. We have a plus R. B squared, which is our second re agent. This forms our product A. B. three. We want to make sure everything is balanced here. So we're going to write out each of our atoms. We have A and B on both sides. Where on our product side we count a total of three B atoms on are reacting side. We have a total of two B atoms and then we have one atom of A on both sides of our equation. So to balance out our atoms of B, we're going to place a coefficient of two in front of our product A. B. Three, which is now going to give us a total of six moles of B on the product side, and now two moles of A on the product side. Where now to compensate for that change on the reactant side, we're going to place a coefficient of three in front of our B. We use a different color. So we have a coefficient of three in front of our B on the reactant side, which now gives us a total of also six moles of B on the reactant side, where we now need to fix our molds of A on the reactant side, meaning that if we place a coefficient of two in front of a will now have also two moles of a, meaning our equation is balanced. So now we have our balanced equation. We want to recognize that according to the prompt A being, our green spheres, which are individual molecules here in our first image are now consumed into a structure here with bonds between our orange spheres forming our A. B. Three product. And so we would say that all of our four moles of a r. Green spheres are consumed to form four moles of a. B. Three. And so we would say that since A is completely consumed A is the limiting reactant. And so to calculate our moles of our product, A. B. Three that are formed using one Molavi and one mole of B squared. We're going to begin with our first reactant, one mole of a. We're going to multiply this by a conversion factor to cancel out moles of a. To get to our product moles of a B three by utilizing the molar ratio from our balanced equation where we see that we have for two moles of A and equivalence of two moles of our product A. B. Three. So we have a 2 to 2 molar ratio. So now we can cancel out our moles of a leaving us with molds of our product A. B three and what we're going to get here is one times two divided by two, which is going to leave us with one mole of our product, A B three. And so for our final answers, we've confirmed that A is our limiting reactant and we have one mole of our product, A B three that forms from one mole of A and one mole of B squared. So I hope that everything I explained was clear. If you have any questions, please leave them down below and I will see everyone in the next practice video.