A compound of formula XCl₃ reacts with aqueous AgNO₃ to yield solid AgCl according to the following equation: When a solution containing 0.634 g of XCl₃ was allowed to react with an excess of aqueous AgNO₃, 1.68 g of solid AgCl was formed. What is the identity of the atom X?

Video transcript

Hello everyone in this video. We're given this reaction over here and were given certain details of the amount of mass per reagent. We're being asked was the name of item X. And that's what we're trying to sell for. Well first let's do some dimensional analysis. So we're starting off with the given of 2. g of our solid a gcl. Then we can go ahead and use the molar mass of a gcl to convert our units into moles of a gcl. So for every one mole of a G C. L, we're able to get one for 3.32 g of a G C L. C. Here that the units of grounds will cancel. Then we can use the store geometric multiple ratio and our compound a gcl which then is just for every two moles of a gcl. We get one mole of AGCL. Or apologize just one mall of flooring here on the top. Alright now using the molar mass of chlorine, we can go ahead and cover it to the mass of chlorine. So for every one mole of chlorine we get 35.453 g of cl. So again then our mole of a gcl will cancel and moles of CLL council. So putting all these values into the calculator. I get the total of 0.6 to 58 g units being grams of chlorine. So our X. C. L. Two which is this here, our first star material. It's where all of our chlorine and are a gcl come from. So we'll focus on that. So how we get the name of the item of X. We can solve for the mass of this and compare it to our periodic table values and see which one we'll go ahead and align. So the mass of X. Is equals to the mass of X. C. L. Two minus the mass of our chlorine. Alright so plugging in the values then it's 1.20 g given to us in problem. And we calculate for the mass of our chlorine to be 0.6 to 58 g. Right? So once we put that to calculator we get the value of 0.5742 g. All right now getting this ground value, we also need to of course find the moles of our unknown R. X. So starting off with the mass of chlorine night is already sulfur that we just did earlier. In the first step that was 0. g of chlorine. We can go ahead to use the molar mass of chlorine to go back into the mold of chlorine. So we have again the 35.453g of chlorine for every one mole of chlorine. So the units of grounds will cancel. Then we'll go ahead and use the historical metric values again. So for every two moles of chlorine we have one mole of our X. Item. So the mole of chlorine will cancel. So putting all these values into the calculator, I get the value of 0.008825 moles of our unknown atom x. So the molar mass of our X. Let's see. So we know that miller mass is grams per mole. So with that equation in mind. So again we're solving for the molar mass of X. So we saw for the g in blue that 0.5742 g. Over again calculated moles of purple of 0.008825 moles. And we get that the molar mass of our unknown item X. Is equal to 65.651 g per mole. And we're looking at our pr table what outlines or what matches this value is going to be ZN. So finally we can identify that the name of adam X. Is equal to the end, which is just zinc. Alright, and that's going to be my final answer for this problem. Thank you all so much for watching