Six isomers for a square planar palladium(II) complex that contains two Cl-and two SCN-ligands are shown below.

(a) Which structures are cis-trans isomers?

(b) Which structures are linkage isomers?

Video transcript

Hi, everybody. Let's take a look at our next question are the following isomers for a square planar nickel, two complex containing two cyanide and two ammonia ligands, cyran isomers. And so we have two square planar complexes with nickel in the center, one of which has the ammonia ligands 180 degrees from each other. And the same obviously with the cyanide ligands and one of which has them 90 degrees apart. So they look like they're on the same side. Two cyanide is on the same side, the two ammonia on the same side. And our answer choices are just a yes, they are cist trans lymm or B. No, they are not cranmer. Well, we see that both of these have the exact same um atoms, the exact same groups in the same geometry. So both are square planar, both have two cyanide, both have two ammonia. The only difference is weather. The identical ligands are 90 degrees or 181 180 degrees apart. And that does make them cis trans isomers or answer is choice a yes. They are. The cis arrangement is where the similar ones are 90 degrees apart. And the trans, when they are 180 degrees apart, think trans across. So they're across from each other. This can be this kind of arrangement can be seen in octahedral or square square planar complexes. But just when you have these two groups of two, obviously, if there was only, there were only one ligand different from the others, you would not see that. So once again, are these two complexes cyran isomers and the answer is choice. A yes, they are. See you in the next video.