How much energy (in kJ/mol) is produced in the following fission reaction of plutonium-239?

Question

How much energy (in kJ/mol) is produced in the following fission reaction of plutonium-239? <CHEMICAL EQUATION>

Accepted Answer

Well, everyone's on this question being asked to calculate the energy in joules per mole released in the fission reaction of uranium 2 35. That's shown below. So it's going to be about this reaction right over here, Russell, given certain masses here All the way through here. So step one is to calculate the mass defect. So Delta M. So one is the mass defect also known as just delta M. So what is delta M. Delta M is equal to the products for the masses of the products minus those of the reactions. So now plugging in some values here, since we are given the masses, it's equal to let's see we have 36. AM you plus nine or 96. AM. You plus two times 1.00867 AM. You minus 35. AM. You plus 1. AM you. So once you put everything into the calculator, let's go ahead and start simplifying this. So for my first part of the subtraction we have 235 points 0.8 five 390 A. M. U. And on the right side of this subtraction, we have 236. a. m. U. So again, putting this into the calculator and finding the final difference, that is equal to negative 0. AM you. So this is the delta M. So the mass defect First step to we have to calculate the mass defect. So delta M in grams per moles. Alright, so my delta M. Is equal to negative 0.19870. We have the units being an A. M. You again we want grams per moles. So then for every 1.6605, 4 Times 10 to the negative 24 g We have one am you. And then we're gonna go ahead and multiply this by avocados number. So 6.022 times 10 to the power. 33rd Power of grams for everyone more. Earlier when I said it was grams. This is actually false because we know that The 6.022 times 10 to the 23rd is of any unit per every one more. So we're gonna use the number for his sake. Alright, so we can see here for the unit consolation. But the A. M. You will cancel. We're being left with just the grams over moles. So once you put this in the calculator, we see that we get the numerical value to be negative 0.19870 units being g per mole. All right Now, last step here, step # three have to go ahead and calculate for the energy released and this is just delta E. Capital. Alright, So delta E. Is equal to delta M C squared. We have these values here so we can go ahead and plug those in. So this is equal to negative 0. g. We're gonna do a unit conversion here from grams into kilograms for every one kg that we have. We have 1000 g and then we're gonna go ahead and multiply this By the speed of light. So that's 3.00 times 10-8. Power units being meter for a second. Go ahead and square this like the formula suggest now we get the adult E. Is equal to after some certification negative 1.79 times 10 to the 13th power it's being kilograms times more times M squared, divided by a squared times more. The same thing as just kilograms times m squared over S squared. So that was just E. The delta E. Going to negative 1.79 times 10 to 13 power units being jewels per mole. And finally we can go ahead and convert jewels into killer jewels. And that is just for everyone. Kill a jewel that we have. We have 1000 jewels. So once you put this in the calculator, we get them. My final Delta E is equal to negative 1.79 times 10 to the 10th Power units being killed jules Permal. And this right here is going to be my final answer for this problem

How much energy (in kJ/mol) is produced in the following fission reaction of plutonium-239?

Verified Solution

Key Concepts

Nuclear Fission

Energy Release in Reactions

Calculating Energy from Mass Defect