Sketch a cell with inert electrodes suitable for electrolysis of aqueous CuBr2. (b) Indicate the direction of electron and ion flow.

Video transcript

Hello. Everyone in this video we're trying to draw a cell set up for the electrolysis of molten lbr three and indicate the direction of the flow of electrons. So over here, given my molecule that we have, we know that my half reactions which of course just can be found either in your textbook found online. But these are just equations and the values that I have on my end. So I'm just gonna go ahead and try to squeeze everything here in this middle portion of my paper starting off with the cathode. End the reaction that I have here. I'll just move this over to the side actually. So we have two moles of our aluminum three plus it's a liquid riding. Six moles of electrons are just six electrons. This yields two moles of R A L Aluminum solid. The standard reduction potential value here is negative 1.662V. And then over on my A node end we have six moles of R B r minus again in its liquid state. This yields three moles of my br two in its liquid state. As well as six electrons. The standard reduction potential for this half reaction is equal to 1.066V. Alright, so for my overall net reaction then let's maybe do it in a different color. Let's do this in purple. So again we have our overall net reaction. Let's see what council's out first. So we have my six electrons canceling. So we have then for my stir first start material is the two moles of R A. L. Three plus As well. Our six moles of BR -. And this yields two moles of our aluminum and solid state as well as three moles of RBR two in its liquid state. And then for our starter reduction potential. Then just subtracting each other is equal to negative 2.728V. So this means that we have a electronic cell and in the cell the and it is the positive terminal which are while the Catholic then is going to be of course are negative terminal. So electrons will basically still flow from the an ode to the cathode. And given all our different choices here from diagram A, C, B and D. The one that boat that just fits our equation and the values that we have is going to be answer choice A where we have the again, electrons flowing from the unknown into the cathode. And we have our different um inert electrodes that's respectfully labeled as well. So then my final choice for this is going to be answer choice. A Again, it's because we calculate these values here and we make sense of our current chemical knowledge