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Ch.19 - Electrochemistry

Chapter 19, Problem 150

Chlorine can be prepared in the laboratory by the reaction of hydrochloric acid and potassium permanganate. (b) Calculate E° and ∆G° for the reaction

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Hello in this problem we are told that flooring is prepared via electrolysis. The following are the half reactions were asked to find the standard cell potential. And the change in gibbs free energy for the reactions. So we begin by writing the overall reaction. So combining the cathode and an half reactions. So we see that we have two electrons being gained, two electrons being lost. So those were canceled. We then combine what's on the reacting side. We have to hydra nines plus two Floridians goes to form. Then hydrogen gas and chlorine gas. Standard cell potential. Then we're going to add the standard cell potential at the cathode to that at the anodes. So we get zero volts plus a negative 2.87 volts. This works out to negative 2.87 volts. And then we're gonna find the change in gibbs free energy. Making use of the relationship between the change of gibbs free energy and the standard cell potential. So we have in two modes of electrons that are being exchanged. So I have negative two moles of electrons will make use of the fair day. So the charge On one more of electrons. And then we'll multiply that by our standard cell potential -2.87V. We call that one jewel is one volt. And then we're gonna convert our jewels to kill jules. So our moles of electrons cancels. Coolants cancels, votes cancels and jewels cancels. So we're left with killed jules. This works out to them 554 killed jules. So our standard cell potential is negative 2.87V and are changing. Give strategy is 554 killed Jules is then corresponds to answer d. Thanks for watching. Hope this helps.
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