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Ch.18 - Thermodynamics: Entropy, Free Energy & Equilibrium

Chapter 18, Problem 78a

For the vaporization of benzene, ∆Hvap = 30.7 kJ/mol and ∆Svap = 87.0 J/(K*mol). Calculate ∆Ssurr and ∆Stotal at: (a) 70 °C

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well everyone in this video, we're being told our delta age of vaporization value and the delta S. Of vaporization value. We're being asked to calculate the delta S of surroundings and the delta as total at degrees Celsius. So for my formula for delta S total, this is equal to my delta us of the system, plus my delta us of the surroundings. So my delta as of the system is also equal to The Delta s. of vaporization was equal to which were given to be jewels per kelvin times more. So we know that the formula for adult us of surroundings is equal to negative delta H. Of vaporization over T for temperature were given the temperature to be 60°C. Let's go ahead and convert this into Kelvin's. We can do this by adding this number by 700 or 273.15 Kelvin's. We get the sum then to be 333.15 Kelvin's. Now for my delta s. Of surroundings, go ahead and use this value here. So we have negative 31.3 killer jewels per mole of course want our killer jewels unit to be in jewels. So for every 1000 jewels we have one killer jewel, Then we're gonna go ahead and divide this with tea, which we sell for above. That's 3 33.15 Calvin's. Once I put that into the calculator, we see that my delta s of surroundings is equal to negative .9517 jules per kelvin times more for units. We just cancel out our killer jewels. All right now for my delta as total. Then let's go ahead and plug in those values. So we already said earlier that my delta system is also equally delta of vaporization, that's 95 jewels per kelvin times more. And then we're gonna go ahead and add this with the delta S. Of surrounding. So that's negative 93.9517 minutes being jewels per kelvin times small. So the units do match, we can simply go ahead and just add those two numbers up so you get them by delta S of total. Is that equal to 1. 483 jewels per kelvin times more. Now to finalize my answers again, we're being asked for the delta S of surroundings and this value is equal to negative 94 jules per kelvin times more were also being asked for the delta S. Total value. And this happens to be 1.0 joules per kelvin times more. So this right here is going to be my final answer for this problem