The following pictures represent initial concentrations in solutions that contain a weak acid HA (pKa = 6.0) and its sodium salt NaA. (Na+ ions and solvent water molecules have been omitted for clarity.)

. (c) Draw a picture that represents the equilibrium state of solution (1) after the addition of two OH-ions.

Video transcript

Hello everyone today. You have the following question. The following are representations of the initial concentrations of a weak acid with the following PK and it's potassium salt, cayenne draw representation of the equilibrium state of solution for upon the addition of one hydroxide ion. The potassium ions and water ions were omitted for clarity. So when we add in one hydroxide ion we add in one hydroxide ion to this solution. For here, the weak acid H. A. Is going to react to neutralize the added base. So what is that gonna look like? That's going to look like R. H. A. Reacting with our hydroxide to neutralize it. We're gonna get the conjugate base and we're also going to get water. So in total one of our acids will be consumed in the reaction with one hydroxide resulting in one additional conjugate base. So from this from four we see that we have three conjugate base initially and now there will be a force. So we had three of these acids reacting to form three of these conjugate bases and adding one more will result in an additional conjugate base. And so the number of our acids Will decrease from three. 22 because the consumption of one acid will be the will react with one hydroxide. And so the correct representation that shows two of our acids and four of our conjugate bases is anti choice. A and with that we've answered the question overall. I hope that this helped and until next time