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Ch.15 - Chemical Equilibrium
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All textbooksMcMurry 8th EditionCh.15 - Chemical EquilibriumProblem 153a

Chapter 15, Problem 153a

The equilibrium constant Kc for the gas-phase thermal decomposition of cyclopropane to propene is 1.0 ⨉105 at 500 K:

(a) What is the value of Kp at 500 K?

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Hello. Everyone in this video. We're given the equilibrium constant KFC. Which is given to us here. But we're being asked what is the KFP at 700 Kelvin's first recognize that the equation for K F P is equal to our equilibrium constant, multiplied by r f T raised to the power of delta N. So delta N is the moles of gas. Let's actually write this out as well. So delta N is equal to the moles of gas regarding our products, minus the moles of gas regarding our directives. So we just take a look at the multiple ratio here from this equation here, we just have one of our server material and one of our products. So basically we have a 1-1 ratio. So 1 -1. That means that our delta end is equal to zero. So we plug that in here. So we get that the K f p is equal to well, the KFC again is given to us 3.0 times 10 to the four. Then we have our F. T. We're just going to ignore that and leave it as is because our delta N is equal to zero. So anything raised to the power of zero is of course just equal to one. So we're basically having our equilibrium constant multiplied by one, Meaning that our KFP constant here is just equal to the same thing as our KFC. So 3.0 times 10 to the fourth power. So this right here is going to be my final answer for this problem
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Halogen lamps are ordinary tungsten filament lamps in which the lamp bulb contains a small amount of a halogen (often bromine). At the high temperatures of the lamp, the halogens dissociate and exist as single atoms. (c) When the WBr41g2 diffuses back toward the filament, it decomposes, depositing tungsten back onto the fila- ment. Show quantitatively that the pressure of WBr4 from part (a) will cause the reaction in part (a) to go in reverse direction at 2800 K. [The pressure of Br1g2 is still 0.010 atm.] Thus, tungsten is continually recycled from the walls of the bulb back to the filament, allow-ing the bulb to last longer and burn brighter.
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Textbook Question
The F ¬ F bond in F2 is relatively weak because the lone pairs of electrons on one F atom repel the lone pairs on the other F atom; Kp = 7.83 at 1500 K for the reaction F21g2 ∆ 2 F1g2. (b) What fraction of the F2 molecules dissociate at 1500 K?
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The F-F bond in F2 is relatively weak because the lone pairs of electrons on one F atom repel the lone pairs on the other F atom; Kp = 7.83 at 1500 K for the reaction F2(g) ⇌ 2 F(g). (c) Why is the F-F bond in F2 weaker than the Cl-Cl bond in Cl2?

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Textbook Question

The equilibrium constant Kc for the gas-phase thermal decomposition of cyclopropane to propene is 1.0 * 105 at 500 K:

(c) Can you alter the ratio of the two concentrations at equilibrium by adding cyclopropane or by decreasing the volume of the container? Explain.

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Textbook Question

Acetic acid tends to form dimers, (CH3CO2H2), because of hydrogen bonding: The equilibrium constant Kc for this reaction is 1.51⨉102 in benzene solution but only 3.7⨉10-2 in water solution. (a) Calculate the ratio of dimers to monomers for 0.100 M acetic acid in benzene.

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Textbook Question

Acetic acid tends to form dimers, (CH3CO2H2), because of hydrogen bonding: The equilibrium constant Kc for this reaction is 1.51⨉102 in benzene solution but only 3.7⨉10-2 in water solution. (b) Calculate the ratio of dimers to monomers for 0.100 M acetic acid in water.

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