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Ch.13 - Solutions & Their Properties

Chapter 13, Problem 61

How would you prepare each of the following solutions? (a) 100 mL of a 155 ppm solution of urea, CH4N2O, in water

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Hello everyone in this video. We want to describe the preparation of a 250 millimeter 102 PPM solution of salicylic acid in water. So this abbreviation of PPM. That stands for parts per million. And how can express this is one P p. M. You're going to one mg of salute for every one liter of solution. Alright, so the first step and this problem is to determine the mass of our asset. So we're given that we have the concentration of 102 ppm. So this would just mean that we have 102 mg of our acid for every one leader of our solution. So cal Boeing for the mass of the salute, We can use this concentration as a conversion factor. So 102 mg on top and then one liter of solution as our denominator. We go ahead and multiply this by ml. These units cannot cancel. So we'll go ahead and convert this unit as well. So just continue this dimension analysis so we can have for every ml we have one leader. So you see now that for the volume units we can go ahead and cancel this and make it into just leaders which will cancel with this like So so once you put everything into the calculator We see the numerical value that we get is 25.5 and the units will of course just be milligrams. So the preparation would be to dissolve. So let's actually write this out is to dissolve 25.5 mg of salicylic acid, 250 ml of water. So this right here is going to be my final answer for this problem.