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Ch.12 - Solids and Solid-State Materials
Chapter 12, Problem 134

The mineral magnetite is an iron oxide ore that has a density of 5.20 g/cm³. At high temperature, magnetite reacts with carbon monoxide to yield iron metal and carbon dioxide. When 2.660 g of magnetite is allowed to react with sufficient carbon monoxide, the CO₂ product is found to have a volume of 1.136 L at 298 K and 751 mm Hg pressure. (a) What mass of iron in grams is formed in the reaction? (b) What is the formula of magnetite?

Verified step by step guidance
1
Step 1: Write the balanced chemical equation for the reaction of magnetite (Fe₃O₄) with carbon monoxide (CO) to produce iron (Fe) and carbon dioxide (CO₂).
Step 2: Use the ideal gas law, PV = nRT, to calculate the number of moles of CO₂ produced. Convert the pressure from mm Hg to atm and use R = 0.0821 L·atm/mol·K.
Step 3: Use stoichiometry to determine the moles of iron produced. From the balanced equation, find the mole ratio between CO₂ and Fe.
Step 4: Calculate the mass of iron produced using the moles of iron and the molar mass of iron (55.85 g/mol).
Step 5: Determine the formula of magnetite by recognizing it as Fe₃O₄, a common iron oxide mineral.