If the band-gap energy of a gallium phosphide (GaP) semiconductor is 222 kJ/mol, calculate the wavelength of light emitted in a GaP light-emitting diode (LED). (LO 12.11) (a) 186 nm (b) 245 nm (c) 539 nm (d) 854 nm

Video transcript

everyone. So ask the wavelength of light of a photon that we have the energy equal to the band gap of any. Um And tomorrow night this is gonna be I. N. Sp. And the band gap of any. um antimony 9 0.18 electron volts. Which we can look up and we're gonna use your place in wavelength equal to Planck's constant times the speed of light divided by the energy to find the wavelength of light. We know the one electron volt. It was 1.602 am. sentence of 19 jewels. We're looking for the wavelength. Thanks constant is 6.626. I'm centenario 34. Those 10 seconds The speed of light is 3.0. I'm sent to the eight m/s. And for the energy 0.18 electron volts. But we need to put it into jewels On one electron volt. 4.602 from Santa May of 19 goals. Can we get 2.88 since in May of 20 jaws. And as you plug in the values we're gonna have for the wavelength 6.626. I'm Santa # 34. Just 10 seconds Times 3.0 Thompson to the eight m/s. By by 2.88. I'm santa mega 20 jewels. We get 6.9 out of 10 to the -6 m. The wavelength. Thanks for watching my video and I hope it was helpful