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Ch.9 - Thermochemistry: Chemical Energy
Chapter 9, Problem 135

9.135 Suppose that a reaction has ΔH = + 41 kJ and ΔS = - 27 J/K. At what temperature, if any, will it change between spontaneous and nonspontaneous?

Verified step by step guidance
1
Step 1: Understand the relationship between Gibbs free energy (ΔG), enthalpy (ΔH), and entropy (ΔS) using the equation ΔG = ΔH - TΔS, where T is the temperature in Kelvin.
Step 2: Recognize that a reaction changes from spontaneous to nonspontaneous when ΔG = 0. This is the condition for equilibrium.
Step 3: Set the equation ΔG = ΔH - TΔS to zero and solve for the temperature T. This gives T = ΔH / ΔS.
Step 4: Convert the units of ΔS from J/K to kJ/K to match the units of ΔH. Since 1 kJ = 1000 J, divide ΔS by 1000.
Step 5: Substitute the values of ΔH and the converted ΔS into the equation T = ΔH / ΔS to find the temperature at which the reaction changes between spontaneous and nonspontaneous.