Balance the following equations. (d) NO 2 + H 2 O → HNO 3 + NO

Hey everyone. We're asked to balance the following chemical reaction. We can start by counting the number of atoms we have on both sides. Starting off with our calcium in our react inside we have three of calcium, two of nitrogen, two of hydrogen and one of oxygen. Looking at our product side, we have one of calcium, one of nitrogen, five of hydrogen and two of oxygen. We can start off by balancing out our calcium by adding a three prior to our calcium hydroxide. When we do this, we end up with three of calcium, nine of hydrogen and six of oxygen. Looking at our nitrogen, we can balance this out by adding a two prior to our ammonia. When we add this to, we change our nitrogen into two And we also change our hydrogen from a nine into a 12. Now to finish off this question, we can balance off our hydrogen and oxygen by adding a six prior to our water. So we end up with 12 of hydrogen and six of oxygen and this will be our final balanced chemical equation. So I hope this made sense. And let us know if you have any questions

Ch.3 - Mass Relationships in Chemical Reactions

All textbooks

McMurry 8th Edition

Ch.3 - Mass Relationships in Chemical Reactions

Problem 40d

Previous problem

Next problem

Chapter 3, Problem 40d

Balance the following equations. (d) NO₂ + H₂O → HNO₃ + NO

Verified step by step guidance

Identify the number of each type of atom on both sides of the equation: NO_2 + H_2O → HNO_3 + NO.

Count the atoms for each element: N, O, and H. On the left, there are 1 N, 2 O from NO_2, and 2 H, 1 O from H_2O. On the right, there are 1 N, 3 O from HNO_3, 1 N, 1 O from NO, and 1 H from HNO_3.

Balance the nitrogen atoms first. There are 2 N on the right (1 from HNO_3 and 1 from NO), so ensure there are 2 N on the left by adjusting the coefficients.

Balance the oxygen atoms next. There are 4 O on the right (3 from HNO_3 and 1 from NO), so adjust the coefficients to have 4 O on the left.

Finally, balance the hydrogen atoms. There are 1 H on the right, so ensure there are 1 H on the left by adjusting the coefficients.

Verified Solution

Video duration:

This video solution was recommended by our tutors as helpful for the problem above.

Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Balancing Chemical Equations

Balancing chemical equations involves ensuring that the number of atoms of each element is the same on both sides of the equation. This is based on the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. Coefficients are used to adjust the quantities of reactants and products to achieve balance.

Stoichiometry

Stoichiometry is the study of the quantitative relationships between the amounts of reactants and products in a chemical reaction. It allows chemists to predict how much of each substance is needed or produced in a reaction. Understanding stoichiometry is essential for balancing equations, as it provides the ratios in which substances react and form.

Types of Chemical Reactions

Chemical reactions can be classified into several types, including synthesis, decomposition, single replacement, and double replacement. The reaction in the question involves the formation of nitric acid (HNO3) from nitrogen dioxide (NO2) and water (H2O), which is a type of synthesis reaction. Recognizing the type of reaction helps in predicting the products and understanding the overall process.