A compound of formula XCl 3 reacts with aqueous AgNO 3 to yield solid AgCl according to the following equation: When a solution containing 0.634 g of XCl 3 was allowed to react with an excess of aqueous AgNO 3 , 1.68 g of solid AgCl was formed. What is the identity of the atom X?

Hello everyone in this video. We're given this reaction over here and were given certain details of the amount of mass per reagent. We're being asked was the name of item X. And that's what we're trying to sell for. Well first let's do some dimensional analysis. So we're starting off with the given of 2. g of our solid a gcl. Then we can go ahead and use the molar mass of a gcl to convert our units into moles of a gcl. So for every one mole of a G C. L, we're able to get one for 3.32 g of a G C L. C. Here that the units of grounds will cancel. Then we can use the store geometric multiple ratio and our compound a gcl which then is just for every two moles of a gcl. We get one mole of AGCL. Or apologize just one mall of flooring here on the top. Alright now using the molar mass of chlorine, we can go ahead and cover it to the mass of chlorine. So for every one mole of chlorine we get 35.453 g of cl. So again then our mole of a gcl will cancel and moles of CLL council. So putting all these values into the calculator. I get the total of 0.6 to 58 g units being grams of chlorine. So our X. C. L. Two which is this here, our first star material. It's where all of our chlorine and are a gcl come from. So we'll focus on that. So how we get the name of the item of X. We can solve for the mass of this and compare it to our periodic table values and see which one we'll go ahead and align. So the mass of X. Is equals to the mass of X. C. L. Two minus the mass of our chlorine. Alright so plugging in the values then it's 1.20 g given to us in problem. And we calculate for the mass of our chlorine to be 0.6 to 58 g. Right? So once we put that to calculator we get the value of 0.5742 g. All right now getting this ground value, we also need to of course find the moles of our unknown R. X. So starting off with the mass of chlorine night is already sulfur that we just did earlier. In the first step that was 0. g of chlorine. We can go ahead to use the molar mass of chlorine to go back into the mold of chlorine. So we have again the 35.453g of chlorine for every one mole of chlorine. So the units of grounds will cancel. Then we'll go ahead and use the historical metric values again. So for every two moles of chlorine we have one mole of our X. Item. So the mole of chlorine will cancel. So putting all these values into the calculator, I get the value of 0.008825 moles of our unknown atom x. So the molar mass of our X. Let's see. So we know that miller mass is grams per mole. So with that equation in mind. So again we're solving for the molar mass of X. So we saw for the g in blue that 0.5742 g. Over again calculated moles of purple of 0.008825 moles. And we get that the molar mass of our unknown item X. Is equal to 65.651 g per mole. And we're looking at our pr table what outlines or what matches this value is going to be ZN. So finally we can identify that the name of adam X. Is equal to the end, which is just zinc. Alright, and that's going to be my final answer for this problem. Thank you all so much for watching

Ch.3 - Mass Relationships in Chemical Reactions

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McMurry 8th Edition

Ch.3 - Mass Relationships in Chemical Reactions

Problem 115

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Chapter 3, Problem 115

A compound of formula XCl₃ reacts with aqueous AgNO₃ to yield solid AgCl according to the following equation: When a solution containing 0.634 g of XCl₃ was allowed to react with an excess of aqueous AgNO₃, 1.68 g of solid AgCl was formed. What is the identity of the atom X?

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Write the balanced chemical equation for the reaction: \[ \text{XCl}_3 + 3\text{AgNO}_3 \rightarrow 3\text{AgCl} + \text{X(NO}_3\text{)}_3 \]

Calculate the moles of AgCl formed using its molar mass: \[ \text{moles of AgCl} = \frac{1.68 \text{ g}}{\text{molar mass of AgCl}} \]

Use the stoichiometry of the balanced equation to find the moles of XCl3 that reacted. Since 3 moles of AgCl are produced per mole of XCl3, divide the moles of AgCl by 3.

Calculate the molar mass of XCl3 using the mass of XCl3 and the moles calculated: \[ \text{molar mass of XCl}_3 = \frac{0.634 \text{ g}}{\text{moles of XCl}_3} \]

Subtract the molar mass of 3 Cl atoms from the molar mass of XCl3 to find the atomic mass of X, and identify the element X based on its atomic mass.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions. It involves using balanced chemical equations to determine the relationships between the amounts of substances consumed and produced. In this question, stoichiometry will help relate the mass of XCl3 to the mass of AgCl formed, allowing for the identification of the element X.

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is crucial for converting between the mass of a substance and the number of moles, which is necessary for stoichiometric calculations. Knowing the molar mass of AgCl and the mass of AgCl produced will help determine the moles of XCl3 that reacted.

Chemical Identity and Valency

The chemical identity of an element refers to its unique properties and position in the periodic table, while valency indicates the combining capacity of an element. In this case, understanding the valency of the element X in XCl3 is essential to deduce its identity based on the number of chloride ions it can bond with, which is critical for determining the element X when combined with AgNO3.

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A compound of formula XCl3 reacts with aqueous AgNO3 to yield solid AgCl according to the following equation: When a solution containing 0.634 g of XCl3 was allowed to react with an excess of aqueous AgNO3, 1.68 g of solid AgCl was formed. What is the identity of the atom X?

Verified Solution

Key Concepts

Stoichiometry

Molar Mass

Chemical Identity and Valency

A compound of formula XCl₃ reacts with aqueous AgNO₃ to yield solid AgCl according to the following equation: When a solution containing 0.634 g of XCl₃ was allowed to react with an excess of aqueous AgNO₃, 1.68 g of solid AgCl was formed. What is the identity of the atom X?